Re: RE: Round Off function in SQL

Joe,

You have hit the nail on the head.  The following is much better.  

SELECT integer((decimal(sum(NumVal),11,2) + .5)) FROM File

INTEGER or INT truncates.

Thanks,

David Morris

>>> Joe Giusto <JGiusto@patuxent.com> 01/05 3:04 PM >>>
How about adding .5 to your result and then convert to integer.  
Like INTEGER = DECIMAL# + .5 
Does the integer function truncate or round?
I am not sure about the divide by .5 in the example below.


Joe Giusto II
Patuxent Publishing Company
 <mailto:jgiusto@patuxent.com> mailto:JGiusto@patuxent.com 
http://www.lifegoeson.com <http://lifegoeson.com> 


----Original Message-----
From:   David Morris [SMTP:dmorris@plumcreek.com] 
Sent:   Monday, January 04, 1999 11:03 AM
To:     MIDRANGE-L@midrange.com 
Subject:        Re: Round Off function in SQL

Prakash,

I asked the same question in August, no response.  The best I could 
come up with was the following:

SELECT integer(((decimal(sum(NumVal),11,2) - integer(sum(NumVal))) / .5)) +  
             integer(sum(NumVal)) 
FROM File

In our case it was acceptable but I would like to find a better solution.

David Morris


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