> -----Original Message-----
> From: mi400-bounces@xxxxxxxxxxxx / David Morris
> Sent: Monday, September 20, 2004 12:03 PM
> Here is another non-MI answer. The problem you are trying to solve is
> NP complete.

Interesting.  I'm glad there's a name for it. <g>  Reading up on it, it
appears that this particular problem can be more aptly called a "subset sum

Well, that'll have to be free-time reading, if I get to that point.  I think
I have hit upon an idea (as outlined in a previous post) that will get
results in a fair amount of time.


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