RE: Beginner question re: CPYBTL

Hi Tom,

This would be a fun one to work with.  However, since I am a beginner
(MI) too, probably the experts will have fixed the program before I even
look at it!

Rich Hart (rhart@atcdgis.com)

-----Original Message-----
From: Tom Daly [mailto:tdaly_2002@yahoo.com]
Sent: Friday, October 04, 2002 3:42 PM
To: mi400@midrange.com
Subject: [MI400] Beginner question re: CPYBTL

<PRE>
Hi,

I need to expand a 3 character string to 4 characters
a-la base64 encoding.  C is not available right now -
but MI is.  So armed with Leif's excellent book and an
MI manual I discovered the CPYBTL operation which
appears to be just the ticket.  But it seems no matter
what I try I can not get the expected results.

Expected results:
24 22  9 35

Actual results (repeatedly no matter what gyrations I
try):
00 22 00 00


So what am I missing about CPYBTL?


Here's the code:

                                    /*
12345678123456781234567812345678 */
DCL   DD    SOURCE     CHAR(4)
INIT(X'01100001011000100110001100000000');
                                    /*       97
98      99       0 */


DCL   DD    RECEIVER1  BIN(4) UNSGND;

DCL   DD    RECEIVER2  BIN(4) UNSGND;

DCL   DD    RECEIVER3  BIN(4) UNSGND;

DCL   DD    RECEIVER4  BIN(4) UNSGND;



DCL   DD    RECEIVER   CHAR(1);





/* Do the deed */

CPYBTL     RECEIVER1,  SOURCE,   1,  6;

CPYBTL     RECEIVER2,  SOURCE,   7,  6;

CPYBTL     RECEIVER3,  SOURCE,  13,  6;

CPYBTL     RECEIVER4,  SOURCE,  19,  6;





/* make the results displayable */

CPYBRA     RECEIVER,          RECEIVER1;

CVTHC      MSG-TEXT( 1:2),    RECEIVER;



CPYBRA     RECEIVER,          RECEIVER2;


CVTHC      MSG-TEXT( 4:2),    RECEIVER;



CPYBRA     RECEIVER,          RECEIVER3;

CVTHC      MSG-TEXT( 7:2),    RECEIVER;



CPYBRA     RECEIVER,          RECEIVER4;

CVTHC      MSG-TEXT(10:2),    RECEIVER;





/* display the results */

CALLI      SHOW-MESSAGE,  *,  .SHOW-MESSAGE;
RTX        *;



%INCLUDE SHOWMSG



=-=-=-=-=-=-


Thanks guys!


Tom Daly

</PRE>


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