|
Gene, I see what you mean. But, if you have a MI snippet that was created with: X = ( A + B ) * C; could/would a disassembler actually return either: X = ( C * A ) + ( C * B ); or X = ( A + B ) * C; or X = C * ( A + B ); for different objects compiled with the same source, same compiler? Thanks for bearing with me on this. - Dan Bale (I am *NOT* "Dale" http://archive.midrange.com/midrange-l/200105/msg00281.html ) SAMSA, Inc. 989-790-0507 DBale@SAMSA.com <mailto:DBale@SAMSA.com> Quiquid latine dictum sit altum viditur. (Whatever is said in Latin seems profound.)
As an Amazon Associate we earn from qualifying purchases.
This mailing list archive is Copyright 1997-2024 by midrange.com and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].
Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.