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Gene, I see what you mean.  But, if you have a MI snippet that was created
with:

    X = ( A + B ) * C;

could/would a disassembler actually return either:

    X = ( C * A ) + ( C * B );
 or
    X = ( A + B ) * C;
 or
    X = C * ( A + B );

for different objects compiled with the same source, same compiler?

Thanks for bearing with me on this.

- Dan Bale
(I am *NOT* "Dale"
http://archive.midrange.com/midrange-l/200105/msg00281.html )
SAMSA, Inc.
989-790-0507
DBale@SAMSA.com <mailto:DBale@SAMSA.com>
  Quiquid latine dictum sit altum viditur.
  (Whatever is said in Latin seems profound.)



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