Re: RUNJVA - JVA0122 - return code 143

David Turnidge skrev den 21-04-2008 19:08:

Sheesh.... As I said before, Java and I have had a very short

relationship -

as in none. So *I* don't have a "main()" and wouldn't even know how to
answer your question... I'm going to attempt a call to IBM - after all,

we

are paying good dollars - Hmmmm - or NOT so good dollars - for support!!

Java itself is a rather plain and simple language. The devil is in the
runtime library :)

I was thinking of something like (where HelloWorld is the class you
start with JAVA/RUNJVA)

public class HelloWorld {
public static void main(String[] args) {
try {
main0(args); // the original main() which may croak and die
} catch (Exception e) {
e.printStackTrace();
}
System.exit(0);
}
}

In this way you are sure that the exception is printed to the spool
file, and that the java program exits cleanly.
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