Re: Java Prototyping Questions?

Oops, I didn't specify my problem correctly.  The Java classes are
already written I need to prototype them in RPG ILE.




On Wed, 2004-07-21 at 16:12, Joe Sam Shirah wrote:
>     Hi Robert,
> 
>     I think this answers what you are asking.
> 
> >   1. How do I prototype the someMethod so that it accepts an array.
> 
>     You pretty much have it already.  My preference is to put the brackets
> with the type rather than the variable.  If no access is given, the default
> is package access.  A return type must be given, use void if nothing is
> returned.
> 
> <access>  <ReturnValueType> someMethod( MyClassA[] myClass )
> {
> }
> 
> >   2. How do I define a field to be an array MyClass[].
> 
> MyClass[] myClass;
> 
> 
> >   3. How do I instantiate the array field from 2.
> 
>     Assumes the declaration from above.
> 
> myClass = new MyClass[ NumberOfElements ];
> 
>     Note that all elements are initially null for Object arrays.  You have
> to load it with objects.
> 
>     You can do the declaration and create the array in one step as:
> 
> MyClass[] myClass = new MyClass[ NumberOfElements ];
> 
>     See The Java Tutorial and the Java Language Specification for more
> information about arrays, variable declarations and loading.
> 
> 
>                                                          Joe Sam
> 
> Joe Sam Shirah -        http://www.conceptgo.com
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> 
> ----- Original Message -----
> From: "Robert Upshall" <rupshall@xxxxxxxxxxx>
> To: <java400-l@xxxxxxxxxxxx>
> Sent: Wednesday, July 21, 2004 3:07 PM
> Subject: Java Prototyping Questions?
> 
> 
> > I am trying to prototype a java methods and I have some questions:
> >
> > Example:
> >
> > I have 2 classes, MyClassA and ThatClassB.  ThatClassB has a method
> > someMethod(MyClassA myClass[]).  I have MyClassA and ThatClassB
> > prototyped.
> >
> >   1. How do I prototype the someMethod so that it accepts an array.
> >
> >   2. How do I define a field to be an array MyClass[].
> >
> >   3. How do I instantiate the array field from 2.
> >
> >
> > Robert
> >
> 
> 
> 
> 
> 
> 
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