|
Joe
This gives me the same error. Is perhaps something wrong with my visual age?
Maarte
>From: Joe Teff <joeteff@earthlink.net>
>Reply-To: JAVA400-L@midrange.com
>To: JAVA400-L@midrange.com
>Subject: Re: JDBC Problems
>Date: Tue, 30 Jan 2001 11:18:20 -0500 (EST)
>
>By enclosing all of your logic in a single try-catch block, any error will
>cause the catch to be called. This may leave the connection to the
>database. You should include a finally to remedy that.
>
>
>import com.ibm.as400.access.*;
>import java.sql.*;
>
>public class DisplayAudit {
> public static void main(java.lang.String[] args) {
> Connection conn = null;
> try {
> Class.forName("com.ibm.as400.access.AS400JDBCDriver");
> conn = DriverManager.getConnection("jdbc:as400://KITS01");
> Statement stmt = conn.createStatement();
> ResultSet rs = stmt.executeQuery("select * from " +
> "kleinr.audit");
> while(rs.next()) {
> java.math.BigDecimal custID = rs.getBigDecimal("CDENTL", 0);
> String custName = rs.getString("CDJOB");
> String custStreet = rs.getString("CDUSPF");
> String custCity = rs.getString("CDETYP");
> System.out.println("Customer ID : " + custID);
> System.out.println("Customer Name : " + custName);
> System.out.println("Customer Street : " + custStreet);
> System.out.println("Customer City : " + custCity);
> }
> rs.close();
> }
> catch (Exception e) {
> System.out.println("Exception: " + e);
> e.printStackTrace();
> }
> finally {
> if (conn != null) {
> conn.close();
> }
> }
> }
>}
>
>
>Joe Teff
>
>
>
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