Re: JDBC Problems

Joe

This gives me the same error. Is perhaps something wrong with my visual age?

Maarte


>From: Joe Teff <joeteff@earthlink.net>
>Reply-To: JAVA400-L@midrange.com
>To: JAVA400-L@midrange.com
>Subject: Re: JDBC Problems
>Date: Tue, 30 Jan 2001 11:18:20 -0500 (EST)
>
>By enclosing all of your logic in a single try-catch block, any error will 
>cause the catch to be called. This may leave the connection to the 
>database. You should include a finally to remedy that.
>
>
>import com.ibm.as400.access.*;
>import java.sql.*;
>
>public class DisplayAudit {
>  public static void main(java.lang.String[] args) {
>   Connection conn = null;
>   try {
>    Class.forName("com.ibm.as400.access.AS400JDBCDriver");
>    conn = DriverManager.getConnection("jdbc:as400://KITS01");
>    Statement stmt = conn.createStatement();
>    ResultSet rs = stmt.executeQuery("select * from " +
>     "kleinr.audit");
>    while(rs.next()) {
>     java.math.BigDecimal custID = rs.getBigDecimal("CDENTL", 0);
>     String custName = rs.getString("CDJOB");
>     String custStreet = rs.getString("CDUSPF");
>     String custCity = rs.getString("CDETYP");
>     System.out.println("Customer ID     : " + custID);
>     System.out.println("Customer Name   : " + custName);
>     System.out.println("Customer Street : " + custStreet);
>     System.out.println("Customer City   : " + custCity);
>    }
>    rs.close();
>   }
>   catch (Exception e) {
>    System.out.println("Exception: " + e);
>    e.printStackTrace();
>   }
>   finally {
>    if (conn != null) {
>      conn.close();
>    }
>   }
>  }
>}
>
>
>Joe Teff
>
>
>
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