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On 30/01/2010, at 10:20 AM, hockchai Lim wrote:
printf("num = %017u\n", num); // the result num =
00000000000000001
First you declared num as signed but here you're saying it's unsigned.
The real problem is that you need to tell printf() to expect a long
long. Your code is telling printf() to read only the first 4 bytes of
the long long value. What do you suppose that might contain?
Fixing both your defects gives:
printf("num = %017lld\n", num);
Regards,
Simon Coulter.
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