Re: Basic c question ==> atol

[Scott Klement <c400-l@xxxxxxxxxxxxxxxx>]

That's because %u is an "unsigned int" -- but you've used a (signed) 
long long instead of an unsigned int.

You need to use %lld (ll=long long, d=integer).

printf("num = %017lld\n", num);



On 1/29/2010 5:20 PM, hockchai Lim wrote:
> ok.  Now, I'm having problem converting this long long (64 bits) num back to
> a string.  I use %017u and it gives me a 00000000000000001.  Why oh why
> (can't c be a bit smarter :).
>
> #include<string.h>
> #include<stdio.h>
> #include<stdlib.h>
>
> int main(void)
> {
>   long long num;
>   char sBuf[30];
>
>   sprintf(sBuf, "6027461692     ");
>   num = atoll(sBuf);
>   printf("num = %017u\n", num);      // the result num = 00000000000000001
>   exit(0);
>
> }