So if there is no \0 in buffer before it gets to index, no \0 will be
appended to profile?
-----Original Message-----
From: c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx
[mailto:c400-l-bounces+lim.hock-chai=usamobility.com@xxxxxxxxxxxx] On
Behalf Of Sharon Wintermute
Sent: Tuesday, July 24, 2007 1:03 PM
To: 'C programming iSeries / AS400'
Subject: Re: [C400-L] strncpy(profile, buffer, index);
Strcpy will copy "index" number of characters of "buffer"
to "profile"
strncpy will copy "index" number of characters of "buffer"
to "profile" AND if there is a \0 before you get to "index" it will
stop and place the \0 at the end of profile.
Sharon
-----Original Message-----
From: c400-l-bounces+swintermute=billsoft.com@xxxxxxxxxxxx
[mailto:c400-l-bounces+swintermute=billsoft.com@xxxxxxxxxxxx] On Behalf
Of Elvis Budimlic
Sent: Tuesday, July 24, 2007 12:54 PM
To: 'C programming iSeries / AS400'
Subject: Re: [C400-L] strncpy(profile, buffer, index);
As I understand it, strncpy copies "index" number of characters of
"buffer"
to "profile". Since "index" is less than length of "buffer", a null
character (\0) is not appended to the "profile".
I don't think length of "profile" enters into equation at all (i.e. you
could corrupt unallocated storage if not careful with your "index"
variable).
Elvis
Celebrating 10-Years of SQL Performance Excellence
http://centerfieldtechnology.com/training.asp
-----Original Message-----
Subject: [C400-L] strncpy(profile, buffer, index);
char profile[11];
char buffer[2048];
int index;
strncpy(profile, buffer, index);
does strncpy auto append \0 in profile if index is less than 11 and
buffer is more than 11?
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