Re: XFoot with Qualified DS's

And if it still doesn't make sense, I'll add some spaces
x  =  +1
or
x  =  -1

So if x is currently equal to 3
then 
x=+1
X would then be equal to a positive 1
However
x+=1
X would then be equal to 4

Thanks for the explanation Hans.  This will help me remember which comes 
first.

Rob Berendt
-- 
"They that can give up essential liberty to obtain a little temporary 
safety deserve neither liberty nor safety." 
Benjamin Franklin 




Hans Boldt <boldt@xxxxxxxxxx> 
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11/25/2003 11:24 AM
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Re: XFoot with Qualified DS's






M. Lazarus wrote:

> At 11/25/03 08:57 AM, you wrote:
> 
>> += is a good thing to remember.  Much like the optional factor 1 in 
>> the ADD op code.
> 
> 
>  Does anyone think that the shorthand syntax is a little backwards?
> It replaces this format: X = X + 1 with X += 1.  Shouldn't it be X =+ 
> 1?  It's a little easier to visualize putting the X in between the = and 

> + than having to reverse it.
> 
> 
>  I realize that C and it's derivatives do it that way, I just think that 

> it's a little odd.  JMHO.
> 
>  Hans, would it be possible to have the compiler handle both ways?
> 
>  -mark

Interesting question. Apparently, the first version of C actually 
implemented it as "x=+1;". It was quickly changed to "x+=1;" when it was 
realized that the former had a another and more common interpretation.

(If it's still not obvious what the issue is, think of the difference 
between "x=-1;" and "x-=1;", and consider that the former was allowed in 
the RPG IV language long before the latter was.)

Cheers! Hans


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