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Rick,

I found that I could build a faster routine, but the difference is
trivial in most business applications that are generally
governed by I/O performance. In the routine you posted,
the output variable gets completely replace several times.
walking through the input string and building the output piece
by piece seems to be more efficient. Here is the routine I
converted to use the %replace bif:

http://cvs.sourceforge.net/cgi-bin/viewcvs.cgi/iseries-toolkit/CVSROOT/src/qrpglesrc/replace.irp?rev=HEAD&content-type=text/vnd.viewcvs-markup

I replaced that code with this:

 C                   EVAL      Pos = %SCAN(InpSch :InpStr)
 C                   EVAL      OutStr = InpStr
 C* Replace characters until no more found or at end of string
 C                   DOW       Pos <> *ZERO
 C                   EVAL      OutStr = %REPLACE(
 C                                         InpRpl:
 C                                         OutStr:
 C                                         Pos:
 C                                         %LEN(InpSch))
 C                   EVAL      Pos = Pos + %LEN(InpRpl)
 C* Enough left to search
 C                   IF        Pos + %LEN(InpSch) - 1 <= %LEN(InpStr)
 C                   EVAL      Pos = %SCAN(InpSch :OutStr :Pos)
 C                   ELSE
 C                   EVAL      Pos = *ZERO
 C                   ENDIF
 C                   ENDDO

My test over 500,000 records ran about 2% faster with the first
version.
Some of that difference depends on how many replacements are made
in a given string.

David Morris

>>> rbaird@esourceconsulting.com 01/22/02 12:43PM >>>

Which brings up a question.  do using nested bifs give us a
performance
hit?

ie.  %trim() inside of %scan(), inside of %replace().  just string
handling
bifs?  what about other bifs?

inquiring minds do!

---my original message---
D fld             s             30    inz('frank             n
furter')

C                   dow       %scan('  ':%trim(fld)) > 0
C                   eval      fld = %replace(' ':%trim(fld):
C                             %scan('  ':%trim(fld)):2)
C                   enddo

fld now equals 'frank n furter                '

Rick


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