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Well in that case give your SQL statement a go. Alan Shore NBTY, Inc (631) 244-2000 ext. 5019 AShore@xxxxxxxx midrange-l-bounces@xxxxxxxxxxxx wrote on 03/07/2007 12:42:16 PM:
Yup...I understand what you mean and I agree. The records in each file are unique by mdvnda and mdmdl...there is only one record in each file with those unique values. On 3/7/07, Alan Shore <AlanShore@xxxxxxxx> wrote:Be careful with this - I think Are the records unique, in the sense of mdvnda & mdmdl If these are NOT unique then you wont have a one to one comparison from
1
file to the other file and my thinking is that record 1 on FILEA will
equal
record 1 on FILEB, but record 2, 3, 4 & 5 on FILEB has the same mdvnda
&
mdmdl as record 1 on FILEB, therefore record 1 on FILEA will not equal records 2, 3, 4, & 5 on FILEB. Therefore the count will be 4. Now - I've just re-read what I wrote. God I hope that makes sense. Alan Shore NBTY, Inc (631) 244-2000 ext. 5019 AShore@xxxxxxxx midrange-l-bounces@xxxxxxxxxxxx wrote on 03/07/2007 12:27:43 PM:Does this make sense? Is there a better way? I'm trying to find out
if
two files are the same. Here's my SQL statement: SELECT count(*) FROM firstlib/mhrdclp a, secondlib/mhrdclp b where a.mdvnda = b.mdvnda and a.mdmdl = b.mdmdl and (a.mddual <> b.mddual or a.MDCMFRT <> b.MDCMFRT or a.MDLP <> b.MDLP or a.MDSF <> b.MDSF) File MHRDCLP has the following fields: mdvnda mdmdl mddual mdcmfrt mdlp mdsf I want to see if I have any records that match mdvnda and mdmdl have any of the other four fields different. Thanks! -- This is the Midrange Systems Technical Discussion (MIDRANGE-L)
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