> c  Eval(h)  temp = YourNumber / 10
> c  Eval     YourNewNumber = temp * 10

The original poster wanted to "always round up".  His example was that 101
should round up to 110.  But your code does not do that.  (It would have
to be 105 to round up to 110).

Instead, he probably wants to do something like this:

      eval temp = (YourNumber + 9) / 10
      eval yournewnumber = temp * 10

That way, 101 will round up to 110, but 100 won't.

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