Re: properties file again

I tested it on my local and here is what I see:
The FileUtil.class.getClassLoader().getResource( "boss.properties")
returns a File object with the path as
"file:\C:\jar\Boss.zip!\boss.properties"
When I try to create a FileInputStream with this File object, it failed
with "java.io.FileNotFoundException:
file:\C:\jar\Boss.zip!\boss.properties (The filename, directory name, or
volume label syntax is incorrect)".

It seems like FileInputStream is not capable of understanding classpath
variable and/or not capable of reading a file that is in a zip file.

Below is my test program:
public class Test2 {

public static void main(String[] args) {

File myFile = FileUtil.findFile("boss.properties");
try {
FileInputStream myFileIS = new
FileInputStream(myFile);
Properties prop = new Properties();
prop.load(myFileIS);
System.out.println("loaded");

} catch (Exception ex) {
System.out.println(ex);
}
System.out.println(myFile);
}
}

"James Perkins" <jrperkinsjr@xxxxxxxxx> wrote in message
news:<mailman.5204.1241539916.23468.web400@xxxxxxxxxxxx>...

You actually shouldn't have to change your code. The using of

InputStream

was just a suggestion. It's always the best to use the highest level

object

you can. It just helps you change from a FileInputStream to say a
StringBufferInputStream without changing other code.

If you can debug it, I would check to see what the name of the file is

that

is returned and make sure it's in the JAR or at least your classpath.

The

code looks fine, but my guess would be that it's not found in the

classpath.

--
James R. Perkins


On Tue, May 5, 2009 at 08:42, Lim Hock-Chai
<Lim.Hock-Chai@xxxxxxxxxxxxxxx>wrote:

Thanks James, I was hoping that we do not have to change code for

this.

My project is to move our J2EE application from jBOSS to WAS6.1.

Below are relevent code that does the setFile:

public static File findFile( String fileName ) {
File file = null;
URL url = FileUtil.class.getClassLoader().getResource(

fileName

);
if( url != null ) {
String decodedUrl = null;
try {
decodedUrl = URLDecoder.decode( url.getPath(),

"ASCII"

);
} catch( UnsupportedEncodingException uee ) {
uee.printStackTrace();
}
file = new File( decodedUrl );
}
return file;
}


I'll look to see what the different between FileInputStream in
InputStream.

Thanks