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On Wed, Aug 12, 2020 at 3:00 PM Jon Paris <jon.paris@xxxxxxxxxxxxxx> wrote:

Because you created an 8 digit intermediate by adding 4 to the number. In theory beginChk# could be 9,999,999 so it could become 10,000,003 and the compiler has to assume that.

Good explanation. Much more understandable than the official
documentation on the precision of intermediate results linked to by
Kevin!

If you change it to use %Dec(beginChk# + 4 : 7 : 0 ) it should fix it.

I think this is a better style anyway. It is more explicit and more
self-documenting. Yeah, a little more verbose, but worth it in my
book.

John Y.

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