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Use embedded SQL! ... but you first need to convert your numeric date into a real date and then use the WEEK_ISO (week according the ISO guide lines, i.e. week starts with Monday and the majority of the days in week 1 is from the new year) or WEEK (January first is always in the first week of a year).

Determining the week according the ISO guidelines with SQL from a 9 digit numeric date
Week_ISO(Right(Digits(YourNumDate) concat '000000', 14))

When Using the VarChar_Format Function you can even determine the year:
The following expression will return the Year/Week. If December 29 is in the first week of the next year, you'll get NextYear/01.
VarChar_Format(Timestamp(Right(Digits(YourNumDate) concat '000000', 14)), 'IYYY/IW')

In this way it is possible to group and sort your dates.

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them and keeping them!"
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-----Original Message-----
From: RPG400-L <rpg400-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Booth Martin
Sent: Donnerstag, 10. Oktober 2019 03:26
To: RPG programming on the IBM i (AS/400 and iSeries) <rpg400-l@xxxxxxxxxxxxxxxxxx>
Subject: RPGLESQL group by year, week# descending from a 9/0 field

This seems possible, but so far I haven't unlocked the lock.

Lets say I have a file with dates as 9/0 (i.e., 020191009 for today)

I would like to group those records by week #, descending. The years will wrap, so there has to be a year marker too.

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