Use embedded SQL! ... but you first need to convert your numeric date into a real date and then use the WEEK_ISO (week according the ISO guide lines, i.e. week starts with Monday and the majority of the days in week 1 is from the new year) or WEEK (January first is always in the first week of a year).
Determining the week according the ISO guidelines with SQL from a 9 digit numeric date
Week_ISO(Right(Digits(YourNumDate) concat '000000', 14))
When Using the VarChar_Format Function you can even determine the year:
The following expression will return the Year/Week. If December 29 is in the first week of the next year, you'll get NextYear/01.
VarChar_Format(Timestamp(Right(Digits(YourNumDate) concat '000000', 14)), 'IYYY/IW')
In this way it is possible to group and sort your dates.
Mit freundlichen Grüßen / Best regards
Birgitta Hauser
"Shoot for the moon, even if you miss, you'll land among the stars." (Les Brown)
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-----Original Message-----
From: RPG400-L <rpg400-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Booth Martin
Sent: Donnerstag, 10. Oktober 2019 03:26
To: RPG programming on the IBM i (AS/400 and iSeries) <rpg400-l@xxxxxxxxxxxxxxxxxx>
Subject: RPGLESQL group by year, week# descending from a 9/0 field
This seems possible, but so far I haven't unlocked the lock.
Lets say I have a file with dates as 9/0 (i.e., 020191009 for today)
I would like to group those records by week #, descending. The years will wrap, so there has to be a year marker too.
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