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Since the fifth key is one character, wouldn't there be an error either in
compilation or execution?

On Wed, Aug 15, 2018 at 9:37 AM, Michael Ryan <michaelrtr@xxxxxxxxx> wrote:

I’ll bet it concatenated the value of MyKey6 to the literal ‘R’.

Sent from my iPhone

On Aug 15, 2018, at 9:34 AM, Vinay Gavankar <vinaygav@xxxxxxxxx> wrote:

Hi,

We have a logical file with 6 keys.

We had following code running in Production for about 8 months:

Setll (MyKey1:MyKey2:MyKey3:MyKey4:'R' +
MyKey6) MyFile ;
If not %eof(MyFile) ;
ReadE (MyKey1:MyKey2:MyKey3:MyKey4:'R' +
MyKey6) MyFile ;

We recently discovered the missing colon between the 5th and 6th key when
trying to find the root cause of some missing data in the file. It seemed
that the 2 statements were being executed with just 5 keys.

I was wondering what the compiler did with the 6th parameter in the
statements. When I changed MyKey6 to an undefined variable, the compiler
gave an error.

TIA

Vinay
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