Re: How to Sort Data Structure array with negative values correctly ???

Thanks I will.

On 6/20/2018 4:53 PM, Alan Campin wrote:

If you look at [1]www.think400.dk/downloads.htm you will find a project under
my name called *XVSRTQ - Dynamic sort of data*.

I solved the problem by using two complement. There might be other
solutions.

On Wed, Jun 20, 2018 at 2:43 PM Troy Foster [2]<tfoster@xxxxxxxxxx> wrote:


I have looked an I can't find a solution. This is example of what I am
trying to accomplish. Is it possible? Does anyone have an example?

I get this when it sorts.
NB(1) = 5.
NB(2) = 2.
NB(3) = 0.
NB(4) = -6.
NB(5) = -4.
NB(6) = -3.
NB(7) = 0.
NB(8) = 0.
NB(9) = 0.
NB(10) = 0.

I want to get:

NB(1) = 5.
NB(2) = 2.
NB(3) = 0.
NB(4) = -3.
NB(5) = -4.
NB(6) = -6.
NB(7) = 0.
NB(8) = 0.
NB(9) = 0.
NB(10) = 0.

This is a sample of the code that I use. I

H BNDDIR('QC2LE')

D qsort PR ExtProc('qsort')
D base * value
D num 10U 0 value
D width 10U 0 value
D compare * procptr value

D LastName PR 10I 0
D parm1 like(name)
D parm2 like(name)

D name s 5
D num_names s 10i 0

d ds
D DS 5 dIM(10)
D NB 1s 0 OVERLAY(DS:*NEXT) INZ(0)
d A 1 OVERLAY(DS:*NEXT) INZ(' ')

c eval NB(1) = -6
c eval NB(2) = -3
c eval NB(3) = 5
c eval NB(4) = -4
c eval NB(5) = 2
c eval NB(6) = 0
c Eval A(1) = 'A'
c Eval A(2) = 'Y'
c Eval A(3) = 'G'
c Eval A(4) = 'H'
c Eval A(5) = 'D'
c Eval A(6) = 'B'

c eval num_names = 6

c callp qsort(%addr(NB): num_names:
c %size(name): %paddr('LASTNAME'))
c eval *inlr = *on

P LastName B
D LastName PI 10I 0
D parm1 like(name)
D parm2 like(name)

c select
c when parm1 < parm2
c return 1
c when parm1 > parm2
c return -1
c other
c return 0
c endsl

P E
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