Re: Losing decimal precision...

[Vernon Hamberg <vhamberg@xxxxxxxxxxxxxxx>]

Try putting a %dec function around num2 -

%dec(num2 : 6 : 3)

Not sure this'll work, but something like this does.

Maybe divide by 100.000

Vern

On 11/6/2015 4:59 PM, Robert Rogerson wrote:
> Hi, how do I code this statement so num1 = .123 not .1?
>
> D num1            s              7p 3
> D num2            s              4p 1
>
> /Free
>   num2 = 12.3;
>   num1 = num2 / 100;
> /Endif
>
>
> Can I do this without creating a temp variable?
>
> D num1            s              7p 3
> D num2            s              4p 1
> d num3            s              4p 3
>
> /Free
>   num2 = 12.3;
>   num3 = num2 / 100;
>   num1 = num3;
> /Endif
>
> Thanks,  I think it's one of those Friday afternoon things....
>
> Rob