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select Pro, count(distinct BillPnt) from stopoffs group by Pro having count(distinct BillPnt) > 1
Scott
-----Original Message-----
From: RPG400-L [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of RPGLIST
Sent: Thursday, September 11, 2014 11:09 AM
To: rpg400-l@xxxxxxxxxxxx
Subject: Sql Comparison Statement help needed
I have a file with over 18,000 stop off points, They are grouped according to the pro number and stop off number:
Pro: 198756
Stop: 1
Pro: 198756
Stop: 2
etc.
Within each set I have a field that is used for billing purposes:
BillPnt
Now, all the lines should have the exact same bill point value, it is a 3 alpha field, it can be blank as well.
I need to select all the records where the value is different from one stop off point to another grouped by the pro number.
IE:
BAD
Pro: 198756
Stop: 1
BillPnt: 707
Pro: 198756
Stop: 2
BillPnt: *Blank
GOOD
Pro: 205478
Stop: 1
BillPnt: 200
Pro: 205478
Stop: 2
BillPnt: 200
I need to capture in a new file just the Pro number for those that have a mismatch IE: BAD.
I can group the records, but I'm not sure how to structure the sql statement for the comparison....
Suggestions would be greatly appreciated.
Dutch
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