Re: Want to replace MOVE numeric 8 to numeric 6 in free form

Hi Jon

I think the winner is the arithmetic solution - easy enough to understand with proper names. I like the date versions, though - very clear and self-documenting.

Performance isn't really a big deal, as I've said in a couple other replies.

I'd put it in a subprocedure if I had time - I'm really under a guideline of minimal change in the shortest possible time during a transition project! Sigh!

Cheers
V.

On 8/17/2013 1:02 PM, Jon Paris wrote:

In terms of efficiency your idea is about as good a performer as you are going to get. Only thing I can think of that would be a bit faster would be to prototype the appropriate MI function. But I haven't got time to do that right now.

For sure no matter what approach you use you should bury it in a subprocedure so that anyone coming after you knows what is happening without needing to understand the mechanics.


On 2013-08-17, at 11:39 AM, Vernon Hamberg <vhamberg@xxxxxxxxxxxxxxx> wrote:

I've a zoned 8,0 that is being MOVEd to a packed 6,0. I want to convert
this to free form.

I can think of putting the zoned 8,0 into a data structure with a zoned
6,0 overlaying the last 6 positions, then use an assignment statement.

In the following, I wanted to use CNVDAT instead of CNVDT8. That can
work with fields from a file, didn't work so far, so will use an
assignment of CNVDT8 = CNVDAT for now.

* Allow "MOVE" of 8-digit ot 6-digiy
D DATE8TO6 DS
D CNVDT8 8s 0
D CNVDT6 6S 0 overlay(DATE8TO6 : 3)

Then CNVDT6 should have the value I want - this is 8-digit dates to
6-digit in YMD format.

Is there a better way? I looked at several articles - Bob Cozzi, Jon
Paris, some other forums - none that I saw dealt with the MOVE from a
longer numeric to shorter.

TIA
Vern
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Jon Paris

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