Worked perfectly. Thanks for the help.
Bill
-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of McGovern, Sean
Sent: Monday, July 22, 2013 11:14 AM
To: RPG programming on the IBM i (AS/400 and iSeries)
Subject: RE: SQL Update duplicate records
The following may help ?
UPDATE MYFILE B SET B.DATE = '2013-07-18'
WHERE
RRN(B) IN ( SELECT RRN(C) From MYFILE B, MYFILE C
Where B.PALLET = C.PALLET and RRN(B) > RRN(C)
AND B.DATE = '2013-07-19'
AND C.DATE = '2013-07-19'
-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Milyard, William A.
Sent: 22 July 2013 16:06
To: RPG programming on the IBM i (AS/400 and iSeries)
Subject: RE: SQL Update duplicate records
Thanks for the suggestion but the distinct still did not work.
Bill
-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Rettig, Roger
Sent: Monday, July 22, 2013 10:16 AM
To: RPG programming on the IBM i (AS/400 and iSeries)
Subject: Re: SQL Update duplicate records
Have you tried putting a distinct in your sub-select?
UPDATE MYFILE B SET B.DATE = '2013-07-18'
WHERE
B.PALLET IN ( SELECT *DISTINCT *B.PALLET From MYFILE B, MYFILE C
Where B.PALLET = C.PALLET and RRN(B) > RRN(C)
AND B.DATE = '2013-07-19'
AND C.DATE = '2013-07-19')
On Mon, Jul 22, 2013 at 9:31 AM, Milyard, William A. < William_Milyard@xxxxxxxxxxxx> wrote:
I know I've seen this in the archives but I can't find the solution.
I need to update one field where the entire row is a duplicate. For example:
Pallet Date
915 2013-07-17
915 2013-07-19 Need to change to 2013-07-18
915 2013-07-19
918 2013-07-19
920 2013-07-19 Need to change to 2013-07-18
920 2013-07-19
UPDATE MYFILE B SET B.DATE = '2013-07-18'
WHERE
B.PALLET IN ( SELECT B.PALLET
From MYFILE B, MYFILE C
Where B.PALLET = C.PALLET and RRN(B) > RRN(C)
AND B.DATE = '2013-07-19'
AND C.DATE = '2013-07-19')
I've tried several variations of this statement but it always updates
too many records. I know there other ways to fix this problem but I
have 9 files with hundreds of records so SQL seems to be the best solution.
Any help is appreciated.
Thanks, Bill
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