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To add to my post - there are reasons for making a copy - if those conditions are not met, probably the original variable's address is used - here's the quote -

Some conditions that would cause this are: the passed parameter is an expression or the passed parameter has a different format.


Passing a variable would likely be the same format, and it's not an expression - so there you are!

Vern

----- Original Message -----
Hi Birgitta

I think the key piece is here -

When the keyword CONST is specified, the compiler may copy the parameter to a temporary and pass the address of the temporary. Some conditions that would cause this are: the passed parameter is an expression or the passed parameter has a different format.

The compiler MAY copy to a temporary, but it doesn't have to.

Nice catch!

Vern

----- Original Message -----
Hi,

I just run in the following situation:
I call a procedure that expects an input parameter and an output parameter.
(The output value is only the revised input value).
The first parameter is passed by constant reference.
In the caller I specify the same variable for Input and Output parameter.

First thing that is done in the called procedure is, the output parameter is
cleard.
I expected the content of the input parameter (even though the same
variable/address was passed) stays untouched.
... but after the clear both input and output parameters are empty!

I'm currently working on an 7.1 system.

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"



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