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An alternative that might perform better...

select * from mytbl A
where exists (select from mytbl B
where a.item = b.item and a.vendor <> b.vendor)

My first solution is easier to understand, I'd og with that unless
performance of it is an issue.

Charles

On Mon, Jun 14, 2010 at 1:40 PM, Charles Wilt <charles.wilt@xxxxxxxxx> wrote:
with itemVendor as (select distinct item, vendor from mytbl)
 , dupItems as (select item, count(*) from itemVendor
                      group by item
                      having count(*) > 1)
select * from mytbl
where item in (select item from dupItems)

HTH,
Charles


On Mon, Jun 14, 2010 at 1:24 PM, Dave Petrosky <Dave.Petrosky@xxxxxxxxxx> wrote:
Sorry I was not clearer. I want to be able to distinguish between rows
where the Item is the same, but the Vendor is different, and I want to
see a list of all the records in which this is true. From my example
table, I would like to see all of the 256 rows (since amongst them, the
vendors are all not the same) but would not like to see any of the 303
rows. And I want to see all four(4) 256 rows, even though two (2) of
them share the same vendor.


I have a table where my data would be like

Company Warehouse Item    Vendor
  1        1        256    25
  2        1        256    *blanks
  3        1        256    24
  4        1        256    24
  1        1        303    25
  2        1        303    25

What I am looking to do is generate a list which will show all of the
Item 256 rows (since these rows are not all the same) but not show any

of the Item 303 rows.

David M. Petrosky
Programmer/Analyst
Maines Paper & Food Service, Inc.
101 Broome Corporate Parkway
Conklin, NY  13748
(office) 607-251-7378
dave.petrosky@xxxxxxxxxx
www.maines.net





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