Re: Quick SQL expression evaluation

Not going to work as static SQL, dynamic SQL to the rescue...

d wSqlStmt s 100a varying
d wResults s 10i 0
/free

wSqlStmt = 'values 2+2 into ?';
exec sql
prepare myStmt from :wSqlStmt;

exec sql
execute myStmt using :wResults;

dsply %char(wResults);

*INLR = *ON;
return;
/end-free

HTH,
Charles


On Tue, May 25, 2010 at 8:30 AM, Dennis Lovelady <iseries@xxxxxxxxxxxx> wrote:

I am trying to write a procedure I thought would be extremely simple: a
short SQL evaluation program that would simply take an expression and return
the result of SQL operating on that expression.  For a silly example:

Exec sql set :myResult   = 2 + 2 ;



To minimize complexity, I am passing the '2 + 2' part as a string, so that
the meat of this very short procedure is:

Exec sql setl :myResult = :myExpression ;



But (and, yes, I know I should have expected this) SQL is seeing it as the
string "2 + 2" rather than a pair of values with an operator between them.
Is there an SQL verb/clause that informs the SQL processor that the
following is an expression rather than a string (such as with unix' "expr"
command)?  Or is this just a pipe dream, not worth the effort?



Dennis E. Lovelady
AIM/Skype: delovelady      MSN: fastcounter@xxxxxxxxxxxx
 <http://www.linkedin.com/in/dennislovelady>
www.linkedin.com/in/dennislovelady --
You can't have everything.  Where would you put it?



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