Re: Copying a data structure (source) over another (target) but target has missing fields

If either
1) The names were the same but the order was different
2) The names were different bu the order the same

Then yes.

But in you case, it's not possible directly.

1) Either code each field on its own eval
2) build (import?) a new DS with the same order as one of the
existing, but with names used by the other existing. Then you can just
do:

eval newA = origA;
eval-corr origB = newA;

HTH,
Charles


On Thu, Apr 15, 2010 at 12:15 PM,  <Peter_Vidal@xxxxxxxx> wrote:

Hello all!

This is my challenge: I have a data structure (let's call it "source")
filled with data that I want to copy over another data structure (let's
call it "target").  Both data structures have the same number of fields
(114) and all these fields have the same field attributes on each data
structure (ie. item number: 15 char, standard cost: 19.8 packed, etc...)
but the issue I see is the fact that they have different field names and
they are in different order in the respective data structures.

I want to eventually do something simple like:
EVAL TARGET = SOURCE

Can this be possible?

TIA,

PETER VIDAL
PALL CORPORATION | SR SYSTEM ANALYST @ WH APPLICATION DEVELOPMENT GROUP
10540 RIDGE RD., SUITE 203, NEW PORT RICHEY, FL 34654-5111
727-815-3104 ||| FAX: 727-815-3120 ||| WWW.PALL.COM

"Imagination is more important than knowledge..."
Albert Einstein (1879 - 1955)

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