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This isn't totally accurate. Method overloading in Java depends on the number and type of the parameters, not the return value. While overloaded methods can return different types, the return type itself is not sufficient to overload a method. This is true for C++ as well.
Mark Murphy
STAR BASE Consulting, Inc.
mmurphy@xxxxxxxxxxxxxxx
-----rpg400-l-bounces@xxxxxxxxxxxx wrote: -----
To: "'RPG programming on the IBM i / System i'" <rpg400-l@xxxxxxxxxxxx>
From: "Dennis Lovelady" <iseries@xxxxxxxxxxxx>
Sent by: rpg400-l-bounces@xxxxxxxxxxxx
Date: 01/11/2010 03:51PM
Subject: RE: RPGV?
As Paul mentioned, technically that's casting. But the premise is
the same: The resulting value is populated based on the variable type
of the receiver. The compiler can easily determine what type the
target is and populate it accordingly.
It's overloading. Casting is the practice of causing a function's return
type to be converted to something else after the fact. Overloaded
return-type functions (possible in JAVA, by the way, and I think I C++)
actually (and "natively") return different types of result based upon the
type of result requested.
No doubt the compiler CAN do this. But DOES it? I mean, for any other
operation, is there a varied result type based upon the variable left of
equals? I think not.
Dennis Lovelady
http://www.linkedin.com/in/dennislovelady
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