RE: Like in embedded SQL

The first I would check is the other 2 fields on your where clause. Are
they excluding your record?



From:
Jerry Adams <Jerry@xxxxxxxxxxxxxxx>
To:
RPG programming on the IBM i / System i <rpg400-l@xxxxxxxxxxxx>
Date:
12/29/2009 02:13 PM
Subject:
RE: Like in embedded SQL
Sent by:
<rpg400-l-bounces@xxxxxxxxxxxx>



You need to code if as LIKE '%200%'. Without the closing % it only
matches on those locations that end in 200.

On the other hand, you may not want, for example, A200L, which this would
select.

Jerry C. Adams
IBM System i Programmer/Analyst
--
B&W Wholesale
office: 615-995-7024
email: jerry@xxxxxxxxxxxxxxx


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]
On Behalf Of THarteau@xxxxxxxxxxxxxxxxxx
Sent: Tuesday, December 29, 2009 1:39 PM
To: RPG programming on the IBM i / System i
Subject: Like in embedded SQL

Hi,
Are there any issues when using LIKE in an SQL declare statement?
I have the following line:
/EXEC SQL
+ DECLARE C6 CURSOR FOR SELECT LPROD, LWHS, LLOT, LLOC, LOPB, LISSU,
+ LADJU, LRCT, LIALOC, LISTAT, WLSTS FROM ILIL01 JOIN ILM ON WWHS =
+ LWHS AND WLOC = LLOC WHERE LWHS = :KEYWHS AND LPROD = :PROD AND L
+ LOC LIKE '%200' ORDER BY WLSTS, LLOC FOR FETCH ONLY
/END-EXEC

It seems to work when it finds 11A200 or 22A200, but it is not returning
2A200. Any ideas? Thanks!

<===================================================>

Terri Harteau
Felker Brothers Corporation
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