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So my assumption came true and there is a limit for the usability of %elem.

Thanx for the response.

Regards

Mihael


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Birgitta Hauser
Sent: Thursday, November 05, 2009 2:01 PM
To: 'RPG programming on the IBM i / System i'
Subject: AW: %elem and nested data structures

Hi Mihael,

I also run into the same problems, especially if I wanted to loop through a
sub array and wanted to use For Index = 1 to %Elem(DS.Sub.SubArr).
It seesm %elem will only work for unnested data structures or arrays.
Not sure if it is a bug or if it works as designed.
May be Barbara can enlighten us.

Mit freundlichen Grüßen / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"


-----Ursprüngliche Nachricht-----
Von: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx] Im
Auftrag von Schmidt, Mihael
Gesendet: Thursday, 05. November 2009 13:41
An: RPG programming on the IBM i / System i
Betreff: %elem and nested data structures

Hi,

I have some nested data structures and it seems that %elem is not working
with nested elements. Is that right?



*-------------------------------------------------------------------------
* Variablen

*-------------------------------------------------------------------------
D top ds qualified
D sub likeds(sub1)
D eans 13A dim(10)

D sub1 ds qualified
D sub likeds(sub2)
D eans 13A dim(10)

D sub2 ds qualified
D dan 7P 0
D ean 13A
D eans 13A dim(10)

/free
top.sub.sub.eans(1) = '1234567890123';
dsply %char(%elem(top.eans)); // works
dsply %char(%elem(top.sub.eans)); // does not work RNF0623E
dsply %char(%elem(top.sub.sub.eans)); // does not work RNF0623E

*inlr = *on;
return;
/end-free


Thanx in advance.

Mihael Schmidt
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