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<snip>
not too bad of a chore
dvalue s 20a Inz(' - 1A 2A 3A ')
dnumber s 10s 0
/free
number = %Dec(%XLate('A':' ':value):10:0);
*inlr=*on;
return;
</snip>
Easy for one "invalid" character, but my example was rather simple. If your value is '1Avvx%994' and you want 1994, you can do the following:
d validchars c ' 1234567890'
d c s 3i 0 inz
d value s 20a inz varying
d newvalue s 20s 0 inz varying
c = %check( validchars : value );
dow c > *zeros;
%subst( value : c : 1 ) = *blanks;
c = %check( validchars : value : c );
enddo;
monitor;
newvalue = %dec( value : 20 : 0 );
on-error;
// whatever seems appropriate (can't imagine what would be left besides numerics/blanks)
endmon;
Of course, this assumes no leading/trailing sign and no decimal points, but...in my example, credit card numbers shouldn't have them anyway. YMMV,
--Bruce Guetzkow
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