|
Jon,you
You want something like this ...
*in50 = %bitand( Out(Idx) : x'01' ) <> 0;
Out(Idx) = %bitxor( Out(Idx) : x'b5' );
If, in the common idiom, the value of *in50 has no further use, then
need only the second of the lines.but
If, perchance, you do to all eight 1-character elements of array Out,
you can reduce this to ...
Out = %bitxor( Out : x'b5b5b5b5b5b5b5b5' );
Perhaps there is some form of *ALL-constant which would save typing,
I do not know it. Pointers, anybody?the
Cheers,
Terry.
On Fri, 2009-03-20 at 17:27 -0500, Jon Sinner wrote:
I am trying to convert some code to free format. I have searched
wouldarchived and found many posts about the use of
%BITAND and %BITOR. Maybe it is because it is late on Friday, but I
just do understand the bit masks and how to use these BIF's.
Can someone show me how to convert the following code to free. I
50really appreciate it.
C TESTB '0' Out(Idx)
50OFF
C IF *IN50
C BITON '0' Out(Idx)
C ELSE
C BITOFF '0' Out(Idx)
C ENDIF
C*
C TESTB '2' Out(Idx)
50OFF
C IF *IN50
C BITON '2' Out(Idx)
C ELSE
C BITOFF '2' Out(Idx)
C ENDIF
C*
C TESTB '3' Out(Idx)
50OFF
C IF *IN50
C BITON '3' Out(Idx)
C ELSE
C BITOFF '3' Out(Idx)
C ENDIF
C*
C TESTB '5' Out(Idx)
50OFF
C IF *IN50
C BITON '5' Out(Idx)
C ELSE
C BITOFF '5' Out(Idx)
C ENDIF
C*
C TESTB '7' Out(Idx)
OFF
C IF *IN50
C BITON '7' Out(Idx)
C ELSE
C BITOFF '7' Out(Idx)
C ENDIF
Thanks
Jon
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