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Hard code _any_ past Friday as a constant in the D-specs. Say,
January 5, 2001, for example? Then remove all the complete weeks
between Jan 5, 2001 and your target date. (Weeks are always 7 days
long, so by removing the whole weeks(dividing by 7), you have only the
part week left, That would be the remainder.) That remainder is your
offset.
Don't make this too hard. It really is that simple. lol I had trouble
keeping it simple enough when it was first explained to me
Today (Wednesday, 11/12/2008) minus last Friday (11/7/2008) is 5 days.
Divide by 7 is 0 weeks & 5 days. (Days-in-a-week(7) - Offset(5) =
(Days-until-Friday(2). Today(11/12/2008), plus 2 days is next
Friday(11/14/2008).
Adam West wrote:
My question is, how does the program know when the next Friday is?
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