RE: Finding duplicate customer names

Mike & Carel,

Thanks for the reply.

SOUNDEX was already at the top of my plans.

However, I was thinking I remembered some other techniques.

What I came up with Friday was the following:

insert into ctsc_w/dupcust (
SELECT c.CUSNBR, c.CUSNAM, D.ADDR1, soundex(cusnam) as
name, soundex(d.addr1) as deladr1, d.addr2, soundex(d.addr2)
as deladr2, substr(d.zip,1,5)
FROM customp C left
outer join addrinp D on deladr = d.akey
WHERE c.locnbr = '00B61' and cussts <> 'D'
)

SELECT CUSNBR, CUSNAM, ADDR1, ADDR2, ZIP, NAME, DELADR1, DELADR2
FROM ctsc_w/dupcust A
WHERE exists (select 1 from ctsc_w/dupcust B
where a.cusnbr <> b.cusnbr
and a.name = B.name and a.zip = b.zip
and (( a.deladr1 <> 'Z000'
and a.deladr1 in (B.deladr1,b.deladr2))
or( a.deladr2 <> 'Z000'
and a.deladr2 in (B.deladr1,b.deladr2)))
)
ORDER BY name, deladr1

Thanks again,
Charles

-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx
[mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Carel Teijgeler
Sent: Friday, August 31, 2007 6:22 PM
To: rpg400-l@xxxxxxxxxxxx
Subject: Re: Finding duplicate customer names

Charles,

SQL Function SOUNDEX, perhaps?

Regards,
Carel Teijgeler

*********** REPLY SEPARATOR ***********

On 31-8-2007 at 16:29 Wilt, Charles wrote:

I seem to recall some discussions in the past about various

algorithms
that would help identify

duplicate customers names or some such field where you can't

depend on

an

exact match.

Anybody remember this, or care to share what's worked for you?

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