RE: alarm() not working as expected

I think () is optional. 

-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx
[mailto:rpg400-l-bounces@xxxxxxxxxxxx] On Behalf Of Rich Duzenbury
Sent: Tuesday, January 17, 2006 11:49 AM
To: RPG programming on the AS400 / iSeries
Subject: Re: alarm() not working as expected

On Tue, 2006-01-17 at 10:29 -0600, Lim Hock-Chai wrote:
> I'm using alarm to control timeout on recv() and having the following
> problem: 
>  
> 1) When timeout occur (errno = EINTR), the program will continue to 
> get the timeout error without at least waiting for timeout to occur 
> again (which is set to 10 secs).  Below is a code snap shot.
>  
> 
> C                ...loop start here
> C                   eval      recvData = *blank

>  *       set time out to 10 sec

> C                   callp     alarm(10)

> C                   eval      recvlen = recv(hostSock :%addr(recvData)

> C                                           :%size(recvData)-10

> C                                           :0)

>  *       disable timeout

> C                   callp     alarm(0)

>

>  *   if time out occured, return back to the main procedure to try to

>  *   send the @GO command.


> C                   if        (errno = EINTR)


I thought the compiler would complain if you didn't use parens on
function calls.  Is this code checking a field called errno, or is it
running the function errno()?

Perhaps try it as   if errno() = EINTR ?

Also, on the second time through, perhaps you could tell us the value of
recvlen?  Was it 0?

Regards,
Rich



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