RE: Get source from object?

["Bob Cozzi" <cozzi@xxxxxxxxx>]

Right DBGVIEW(*SOURCE) puts a link to the original source member in the
object; it does not copy the source into the object. DBGVIEW(*LIST) will do
that, albeit the expanded compiler listing version of the source.


-----Original Message-----
From: rpg400-l-bounces@xxxxxxxxxxxx [mailto:rpg400-l-bounces@xxxxxxxxxxxx]
On Behalf Of Scott Klement
Sent: Thursday, July 15, 2004 2:45 PM
To: RPG programming on the AS400 / iSeries
Subject: RE: Get source from object?


Hi Dan,

> Assuming RPG-IV, if you compiled with DBGVIEW(*SOURCE) or DBGVIEW(*ALL)
> then, yes, it's in the object.

Forgive me, but do you mean DBGVIEW(*LIST)?  I thought DBGVIEW(*SOURCE)
meant that the debugger referred back to the actual source member?

The following text appears in the help for the CRTBNDRPG command:

 *SOURCE
     Generates the source view for debugging the compiled program object
     This view is not available if the root source member is a DDM file.
     Also, if changes are made to any source members after the compile
     and before attempting to debug the program, the views for those
     source members may not be usable.

It doesn't directly say that *SOURCE refers to the actual source member,
but it does imply that if you change the source member, what you see in
the debugger may not be relevant -- so to me that implies that it's using
the actual source.

Obviously, if that source were deleted, DBGVIEW(*SOURCE) wouldn't help --
so I'm guessing that you actually meant DBGVIEW(*LIST) -- or that I'm just
totally wrong.

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