Re: Half-Adjust with /free

[mwalter@xxxxxxxxxxxxxxx]

Use %dech() BIF and specify the precision.

Thanks,

Mark

Mark D. Walter
Senior Programmer/Analyst
CCX, Inc.
mwalter@xxxxxxxxxx
http://www.ccxinc.com


                                                                                
                                                        
                      Raul A Jager                                              
                                                        
                      <raul@xxxxxxxxxx>         To:       RPG programming on 
the AS400 / iSeries <rpg400-l@xxxxxxxxxxxx>                
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                      rpg400-l-bounces@m        Subject:  Re: Half-Adjust with 
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                      06/22/2004 10:47                                          
                                                        
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I think eval can not be ommited if you want half adjust:

eval(h) a = b + c;

You can also use %dech or justa add 0.5, like this

a = b + c + 0.5;

michaelr_41@xxxxxxxxxxxxxx wrote:

>I can't believe I haven't encoutered this yet. How does one perform
>half-adjust when using free format?
>
>/free
>  a =(H) b + c;
>
>doesn't seem to work. Do I need to do a %DECH or something?
>
>
>


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