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Eve, here's one method, (using SQL): D Number S 16P 8 Inz(3.75) D Character S 20A D Result S Like(Character) /Free // Convert numeric to a character Character = %Char(Number); /End-Free // Use SQL string functions to save some coding C/Exec Sql C+ Set :Result = Trim(Both '0' From Trim(Both ' ' From :Character)) C/End-Exec /Free // Display results to confirm Result = '<' + %Trim(Result) + '>'; Dsply Result '*REQUESTER'; *InLR = *On; /End-Free Brian Parkins
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