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Let's say I have these three fields defined...

     d MMDDCCYY          s           d        inz    datfmt(*USA)
     d todayISO          s         8s0        inz(20020819)
     d todayUSA          s         8s0   inz

What is the free-format way to convert the date-field to a numbeic... :
-- The old way to do it was :
     c    *ISO MOVE todayISO  MMDDCCY
     c         MOVE MMDDCCYY  todayUSA
-- How would the above be changed...

-- We have someone here who found a C program that would do the trick, but
I wasn't sure if there was an easier way...


David L. Mosley, Jr.
Systems Analyst
2000 CentreGreen Way
Suite 250
Cary, NC 27513



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