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Let's say I have these three fields defined... d MMDDCCYY s d inz datfmt(*USA) d todayISO s 8s0 inz(20020819) d todayUSA s 8s0 inz What is the free-format way to convert the date-field to a numbeic... : -- The old way to do it was : c *ISO MOVE todayISO MMDDCCY c MOVE MMDDCCYY todayUSA -- How would the above be changed... -- We have someone here who found a C program that would do the trick, but I wasn't sure if there was an easier way... David L. Mosley, Jr. Systems Analyst 2000 CentreGreen Way Suite 250 Cary, NC 27513
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