RE: SQL SUBSTRING

["Smith, Mike" <Smith-Mike@xxxxxxxxxxxxxxxxx>]

thanks Rob, 
that was the difference.  I had did not have #LEN defined as Binary.  Now it
works fine. 

-----Original Message-----
From: rob@dekko.com [mailto:rob@dekko.com]
Sent: Friday, December 08, 2000 4:14 PM
To: RPG400-L@midrange.com
Subject: Re: SQL SUBSTRING



Is #LEN defined as (from the SQL manual) 'a binary integer in the range 0
to n'?

The following worked for me:

D #LEN            S              5B 0
D CNTHLD          S              5P 0
D #ID             S              6A

C                   Eval      #len=6
C                   Eval      #id='81.001'
C/EXEC SQL
C+ SELECT COUNT(*) INTO :cnthld FROM ROB/aaakey
C+ where substr(loc,1,:#LEN)=:#ID
C/END-EXEC

C     cnthld        dsply

C                   Eval      *inlr=*on



Rob Berendt

==================
Remember the Cole!


 

                    "Smith, Mike"

                    <Smith-Mike@Crest.ar        To:
RPG400-L@midrange.com                                             
                    amark.com>                  cc:

                    Sent by:                    Subject:     SQL SUBSTRING

                    owner-rpg400-l@midra

                    nge.com

 

 

                    12/08/00 02:47 PM

                    Please respond to

                    RPG400-L

 

 





i need to do a substring in SQL extracting a field of varying size.  I am
pulling this from a flat file.  I can get it to work if i specify an actual
length like this.

C+ SELECT COUNT(*) INTO :CNTHLD FROM MIKELIB/PIFCORP
C+ WHERE SUBSTR(PIFLD,1,:5) =  :#ID

HOWEVER, the length of the substring is of varying length

i have tried to do something like this

C+ SELECT COUNT(*) INTO :CNTHLD FROM MIKELIB/PIFCORP
C+ WHERE SUBSTR(PIFLD,1,:#LEN) =  :#ID

but it doesn't like the variable for the third parm.

Does anyone know how i can accomplish this.

thanks

mike
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