|
Here's another way (untested of course):
0464.00 * replace trailing blanks in amtA with leading zeros
0465.00 c eval amtA = %trim(amtA)
0466.00 c eval x = %scan(' ':amtA)
0467.00 c if x > 1
0468.00 c eval amtA = %subst('000000000000':1:13-x)
0469.00 c + %subst(amtA:1:x-1)
0470.00 c else
0471.00 c eval amtA = '0000000000.00'
0472.00 c endif
Colin Thorpe <Colin@IBS-PUBLIC-SERVICES.CO.UK>
Sent by: owner-rpg400-l@midrange.com
08/17/00 10:11 AM
Please respond to RPG400-L
To: RPG400-L@midrange.com
cc:
Subject: Character to Decimal
Hi all,
I am trying to take a character field (10A) containing something like
123.45bbbbb,
And move it into a numeric field (12,2) 0000000123.45.
The character field may or may not contain a decimal point.
Therefore its value could be from .01 ==> 9999999999
Some time ago the C function ATOL was mentioned by Hans.
I'm using V3R7 and managed to get his example working fine.
Unfortunately this only returns the integer part of the value.
I also tried ATOF but I'm not sure what the resulting value means. 2235.14
= 1079246848 ?
I can solve this problem using data structures and selects but I'm looking
for an elegant ILE solution.
Any help will be greatly appreciated.
Thanks in advance
Colin
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