Date Conversion Problem

["Venkat Sreenivasan" <vsreeniv@xxxxxxxx>]

Hi All

I encountered a strange situation when I ran the following program for testing
the logic.  I do not know whether I understood it wrong or that is how the IBM
date routine works.  Need help.

Source Code:

12       d date             s               d   datfmt(*USA)
13       d date0           s               d   datfmt(*USA)
14       d date1           s              8  0 inz(18980101)
15       d date2           s              8  0 inz
16       d cdate           s             10    inz

22       c     *CYMD         move      date1         date
23       c                   subdur    30:*d         date
24       c     *CYMD         move      date          date2
25       c                   eval      cdate = %CHAR(date)
26
27       c     *CYMD         move      date1         date0
28       c                   subdur    31:*d         date0
29       c                   If        date  > date0
30       c                   eval      cdate = %CHAR(Date0)
31       c                   endif
32
33       c                   eval      *INLR = *ON
34       c                   RETURN

1.   In the above code when I checked the value of DATE after executing line 22
it reads like: 01/01/2798 which is wrong.
2.   After performing a date arithmetic in line 23 the value of DATE looks like
12/02/2797 (difference of 30 days from the         previous step).
3.   After the line 24 execution the value of DATE2 reads like:     18971202
which is correct.
4.   After the execution of line 25 the value CDATE read like:    12/02/2797
which wrong.

I would like to know is there anything wrong with the method I've adopted.
DATE1 is the date that stored in our files and DATE2 is the newly calculated
date which will be updated to another field.   Your help is verymuch
appreciated.

Thanks to all

Venkat Sreenivasan
Metamor Worldwide.


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