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Locate will return the position (in Character) of the first occurrence
(here: blank)

Mit freundlichen Grüßen / Best regards

Birgitta Hauser
Modernization ? Education ? Consulting on IBM i
Database and Software Architect
IBM Champion since 2020

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"
"Train people well enough so they can leave, treat them well enough so they
don't want to. " (Richard Branson)
"Learning is experience ? everything else is only information!" (Albert
Einstein)

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Dan
Bale
Sent: Wednesday, 1 May 2024 16:44
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: RE: Using SQL to replace characters less than Blank

5? There are only 3 spaces in that string. What am I missing? (I
replicated that here as well.)

- Dan

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of VERNON
HAMBERG Owner via MIDRANGE-L
Sent: Wednesday, May 1, 2024 9:57 AM
To: midrange-l@xxxxxxxxxxxxxxxxxx
Cc: VERNON HAMBERG Owner <vhamberg@xxxxxxxxxxxxxxx>;
midrange-l@xxxxxxxxxxxxxxxxxx
Subject: RE: Using SQL to replace characters less than Blank

Hi Birgitta

I like your idea, to use TRANSLATE. If he uses this, I think he should add
control characters, as well, he is trying to replace X'0D'.

Casting, in my opinion, is not needed - both Glenn Gunderman and I used what
was presented and had no problem. As a first attempt I ran this statement in
RSS -

values locate(x'40', 'This has a space')

The result was 5.
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