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I'm not quite sure why you want to get 3 for 046 if I count correctly there
are 4 different nro_invs
You may try the following query

Select CodeVet, Count(Distinct nro_invs)
From YourTable
Group By CodeVet.

Mit freundlichen Grüßen / Best regards

Birgitta Hauser
Modernization ? Education ? Consulting on IBM i

IBM Champion since 2020

"Shoot for the moon, even if you miss, you'll land among the stars." (Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"
"Train people well enough so they can leave, treat them well enough so they
don't want to. " (Richard Branson)
"Learning is experience ? everything else is only information!" (Albert
Einstein)

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of
gio.cot via MIDRANGE-L
Sent: Wednesday, 24 May 2023 20:07
To: 'Midrange Systems Technical Discussion' <midrange-l@xxxxxxxxxxxxxxxxxx>
Cc: gio.cot <gio.cot@xxxxxxxxxxx>
Subject: R: Help with Sql

Sorry .

I hope the table now is more clear



codeVet Year_Inv nro_inv type_inv

000 23 63509 G

046 23 71490 G

046 23 71490 H

046 23 75569 G

046 23 75978 G

046 23 76078 G



Hi all



Suppose i have a table with this data




codeVet

Year_Inv

nro_inv

type_inv


000

23

63509

G


046

23

71490

G


046

23

71490

H


046

23

75569

G


046

23

75978

G


046

23

76078

G



With Sql i would get :



The nro Invoice for every CodeVet_vet excluding the nro_inv the have two or
more row (in this case the nro_inv 23-71490) ; so the result that i would
need, is



CodeVet Nro_inv

000 1

046 3



Thanks in advance

Gio





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