A single quote has to be duplicated, so '%''%' should work.
Mit freundlichen Grüßen / Best regards
"Shoot for the moon, even if you miss, you'll land among the stars." (Les
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not training them
and keeping them!"
?Train people well enough so they can leave, treat them well enough so they
don't want to.? (Richard Branson)
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Alan
Shore via MIDRANGE-L
Sent: Sonntag, 21. November 2021 16:23
Cc: Alan Shore <ashore@xxxxxxxx>
Subject: Using SQL to determine if a field contains any quotes
We are on V7r3
I need to determine the existence of any quotes in a particular field I
tried using SQL like - '%'''%' but its telling me that is wrong, and Im not
sure what to use for a google search Anyone have an idea whats needed
As always - all replies gratefully accepted Alan Shore Solutions Architect
IT Supply Chain Execution
60 Orville Drive
Bohemia, NY 11716
Phone [O] : (631) 200-5019
Phone [C] : (631) 880-8640
E-mail : ASHORE@xxxxxxxxxxxxxxxxxxxx
'If you're going through hell, keep going.'
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