Re: SQL Max question

Hello Art

If I may say back what I think you're saying -

You have a table with 1 row per DID# - that is, DID# is unique.

And status is not in this table.

And you want a result table that has all the columns from the first one, plus a status column that has the highest status for the DID# in that row.

OK, I think you are getting close and can get this with a JOIN and a nested table expression - you want the 2nd table to have the DID# and its highest status in it - then JOIN to that.

select table1.*, table2max.maxstatus from table1
  join (select did#, max(status) maxstatus from table2 group by did#) table2max
    on table1.did# = table2max.did#

Then you can do pretty much what you want - you could create a temp from this using CREATE TABLE, for example, and make it based on this SELECT statement.

HTH
Vern

On 9/5/2020 10:26 PM, Art Tostaine, Jr. wrote:

There is one row in my first table keyed by did. Other tables are joined
into this view but they are 1-1 by did. I joined it to a status file that
has Did and 1-20 statuses/rows.

In my new table I want all of the fields but only one row per did with the
highest status.

My goal is to create a temp table that I can run reports, extract to csv,
etc.

I wonder if I could create one row per did and then do an update with a
select from the status file getting only the max row from it.

On Sat, Sep 5, 2020 at 10:36 PM Alan Campin <alan0307d@xxxxxxxxx> wrote:

I am not completely understanding what you are doing here but normalizing

table structure?



Could you respond with what you see the table structure would look like?



On Sat, Sep 5, 2020 at 6:52 PM Art Tostaine, Jr. <atostaine@xxxxxxxxx>

wrote:

I have a table that has a DID#, many other columns, and a numeric status
field. I want the table to have all the columns and one row per did#

with

the highest status value.
I'd like to either do a delete or create another temp table with only

these

records. Is this possible?
I've looked at group by but that won't let me keep all columns in the
table.
I also checked out partition by but that's not what I want.
Thank you
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Art Tostaine
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Art Tostaine