RE: How to get the dollar value from this text string? -- MIDRANGE-L

Can someone help me to understand this? I hate being ignorant.

I have tried this out and understand that it works - but I do not know why.

'.* ' - How does this tell REGEX that it should match up to and including the last space/blank?

I have read the manual and find nothing that lets me interpret this as replace all characters up to and including the last space.
I have modified the pattern it to '.*N'

values rtrim(regexp_replace ('NTE*OTH*#OH- HANDLING CHARGES GSYE9R03/WHT/ / 4T/- 2.29~', '.*N'), '~');

and it returned

'G CHARGES GSYE9R03/WHT/ / 4T/- 2.29'

Which means it replaced everything up to and including the last 'N' with an empty string.

My question is: How?

Paul

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf Of Niels Liisberg
Sent: Friday, July 31, 2020 3:55 AM
To: Midrange Systems Technical Discussion <midrange-l@xxxxxxxxxxxxxxxxxx>
Subject: Re: How to get the dollar value from this text string?

Agreed Jon, I think I will challenge Birgita on that one:

Here i my one-liner solution: Remove any characters until the last blank, Picup the number and remove the filal ~

**free

dcl-s instr varchar(256);

dcl-s dolar packed( 15: 2);

inStr = 'NTE*OTH*#OH- HANDLING CHARGES GSYE9R03/WHT/ / 4T/-
2.29~';

exec sql values rtrim(regexp_replace (:instr, '.* '),'~') into :dolar;

return;

On Thu, Jul 30, 2020 at 4:33 PM Jon Paris <jon.paris@xxxxxxxxxxxxxx> wrote:

OMG that is UGLY!

On Jul 30, 2020, at 1:56 AM, Birgitta Hauser
<Hauser@xxxxxxxxxxxxxxx>

wrote:

The following SQL-Statement should return the numbers only:
Select Dec(RegexP_Replace(Substr(Text,Locate_In_String(Text, '/',
-1) +

1),

'[\s^~]', ''), 11, 2),
Text
from
(Values('NTE*OTH*#F7- PST/SALES TAX GAZE9H01/MNT/ / 6/- 1,23~'),
('NTE*OTH*#F7- PST/SALES TAX GSYE9R03/WHT/ / 4T/- 1,22~'),
('NTE*OTH*#OH- HANDLING CHARGES GAZE9H01/MNT/ / 6/- 3,36~'),
('NTE*OTH*#OH- HANDLING CHARGES GSYE9R03/WHT/ / 4T/- 2,29~')) x
(Text);

Mit freundlichen Gr en / Best regards

Birgitta Hauser

"Shoot for the moon, even if you miss, you'll land among the stars."
(Les
Brown)
"If you think education is expensive, try ignorance." (Derek Bok)
"What is worse than training your staff and losing them? Not
training

them

and keeping them!"
Train people well enough so they can leave, treat them well enough
so

they

don't want to. (Richard Branson)

-----Original Message-----
From: MIDRANGE-L <midrange-l-bounces@xxxxxxxxxxxxxxxxxx> On Behalf
Of

Kevin

Bucknum
Sent: Mittwoch, 29. Juli 2020 20:04
To: midrange-l@xxxxxxxxxxxxxxxxxx
Subject: Re: How to get the dollar value from this text string?

If you do have regex setup and working from sql on your box, then
this little quick and dirty program extracts everything after the last space.
That includes that ~ but you can remove that.

**Free
Dcl-s V1 Char(100);
Dcl-s Result Char(10);
V1 = 'NTE*OTH*#OH- HANDLING CHARGES GAZE9H01/MNT/ / 6/- 3.36~';

Exec Sql Select Regexp_Substr(
Trim(:V1),
'[\S]+$')
Into :Result
From sysibm.sysdummy1;

Dsply Result;
*Inlr = *On;
Return;

On Wed, 2020-07-29 at 11:48 -0600, Jack Woehr wrote:

the regex for that is something like

.*(\d*\.\d\d).*

when $1 will be your dollar figure.

--

Jack Woehr

Absolute Performance, Inc.

12303 Airport Way, Suite 100

Broomfield, CO 80021

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[https://www.medtronsoftware.com/img/MedtronMinilogo.bmp] Kevin

Bucknum

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