Mod is available.
select mod(7,2) from sysibm/sysdummy1
MOD ( 7 , 2 )

On Wed, 2020-01-15 at 14:08 +0000, Alan Shore via MIDRANGE-L wrote:

Hi everyone

We are on V7r3

Within SQL - how do you determine if fielda divided by fieldb has any remainder

My google search came up with quite a few suggestions (REMAINDER, MOD) that are not available on the iSeries

Alan Shore

E-mail :






Phone [O] : (631) 200-5019

Phone [C] : (631) 880-8640

'If you're going through hell, keep going.'

Winston Churchill

[] Kevin Bucknum
Senior Programmer Analyst
120 Innwood Drive
Covington LA 70433
Local: 985-893-2550
Toll Free: 877-893-2550


This document and any accompanying this email transmission contain confidential information, belonging to the sender that is legally privileged. This information is intended only for the use of the individual or entity named above. The authorized recipient of this information is prohibited from disclosing this information to any other party and is required to destroy the information after its stated need has been fulfilled. If you are not the intended recipient, or the employee of agent responsible to deliver it to the intended recipient, you are hereby notified that any disclosure, copying, distribution or action taken in reliance on the contents of these documents is STRICTLY PROHIBITED. If you have received this email in error, please notify the sender immediately to arrange for return or destruction of these documents.

As an Amazon Associate we earn from qualifying purchases.

This thread ...


Follow On AppleNews
Return to Archive home page | Return to MIDRANGE.COM home page

This mailing list archive is Copyright 1997-2022 by and David Gibbs as a compilation work. Use of the archive is restricted to research of a business or technical nature. Any other uses are prohibited. Full details are available on our policy page. If you have questions about this, please contact [javascript protected email address].

Operating expenses for this site are earned using the Amazon Associate program and Google Adsense.