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So you're looking for something like this?
SELECT JOB_STATUS, COUNT(*)
FROM TABLE(QSYS2.JOB_INFO(JOB_USER_FILTER => 'ROB')) X
GROUP BY JOB_STATUS
ORDER BY JOB_STATUS
JOB_STATUS COUNT ( * )
ACTIVE 4
OUTQ 70

https://www.ibm.com/developerworks/community/wikis/home?lang=en#!/wiki/IBM%20i%20Technology%20Updates/page/QSYS2.JOB_INFO%20UDTF


Rob Berendt

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